(1/5(x)^2)-5=y

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Solution for (1/5(x)^2)-5=y equation: 


x in (-oo:+oo)

(1/5)*x^2-5 = y // - y

(1/5)*x^2-y-5 = 0

1/5*x^2 = -(-y-5) // : 1/5

x^2 = 5*(y+5)

x^2 = 5*(y+5) // ^ 1/2

abs(x) = 5^(1/2)*(y+5)^(1/2)

x = 5^(1/2)*(y+5)^(1/2) or x = -(5^(1/2)*(y+5)^(1/2))

x in { 5^(1/2)*(y+5)^(1/2), -(5^(1/2)*(y+5)^(1/2)) }

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